Optimal. Leaf size=598 \[ -\frac{i b d^3 \text{PolyLog}\left (2,1-\frac{2}{1-i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{e^4}+\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{PolyLog}\left (2,1-\frac{2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{e^4}-\frac{i b^2 \text{PolyLog}\left (2,1-\frac{2}{1+i c x}\right )}{3 c^3 e}+\frac{b^2 d^3 \text{PolyLog}\left (3,1-\frac{2}{1-i c x}\right )}{2 e^4}-\frac{b^2 d^3 \text{PolyLog}\left (3,1-\frac{2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{2 e^4}+\frac{i b^2 d^2 \text{PolyLog}\left (2,1-\frac{2}{1+i c x}\right )}{c e^3}-\frac{d \left (a+b \tan ^{-1}(c x)\right )^2}{2 c^2 e^2}-\frac{i \left (a+b \tan ^{-1}(c x)\right )^2}{3 c^3 e}-\frac{2 b \log \left (\frac{2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{3 c^3 e}+\frac{d^2 x \left (a+b \tan ^{-1}(c x)\right )^2}{e^3}+\frac{i d^2 \left (a+b \tan ^{-1}(c x)\right )^2}{c e^3}+\frac{d^3 \log \left (\frac{2}{1-i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2}{e^4}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{e^4}+\frac{2 b d^2 \log \left (\frac{2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{c e^3}-\frac{d x^2 \left (a+b \tan ^{-1}(c x)\right )^2}{2 e^2}+\frac{a b d x}{c e^2}+\frac{x^3 \left (a+b \tan ^{-1}(c x)\right )^2}{3 e}-\frac{b x^2 \left (a+b \tan ^{-1}(c x)\right )}{3 c e}-\frac{b^2 d \log \left (c^2 x^2+1\right )}{2 c^2 e^2}+\frac{b^2 x}{3 c^2 e}-\frac{b^2 \tan ^{-1}(c x)}{3 c^3 e}+\frac{b^2 d x \tan ^{-1}(c x)}{c e^2} \]
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Rubi [A] time = 0.671122, antiderivative size = 598, normalized size of antiderivative = 1., number of steps used = 23, number of rules used = 13, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.619, Rules used = {4876, 4846, 4920, 4854, 2402, 2315, 4852, 4916, 260, 4884, 321, 203, 4858} \[ -\frac{i b d^3 \text{PolyLog}\left (2,1-\frac{2}{1-i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{e^4}+\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{PolyLog}\left (2,1-\frac{2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{e^4}-\frac{i b^2 \text{PolyLog}\left (2,1-\frac{2}{1+i c x}\right )}{3 c^3 e}+\frac{b^2 d^3 \text{PolyLog}\left (3,1-\frac{2}{1-i c x}\right )}{2 e^4}-\frac{b^2 d^3 \text{PolyLog}\left (3,1-\frac{2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{2 e^4}+\frac{i b^2 d^2 \text{PolyLog}\left (2,1-\frac{2}{1+i c x}\right )}{c e^3}-\frac{d \left (a+b \tan ^{-1}(c x)\right )^2}{2 c^2 e^2}-\frac{i \left (a+b \tan ^{-1}(c x)\right )^2}{3 c^3 e}-\frac{2 b \log \left (\frac{2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{3 c^3 e}+\frac{d^2 x \left (a+b \tan ^{-1}(c x)\right )^2}{e^3}+\frac{i d^2 \left (a+b \tan ^{-1}(c x)\right )^2}{c e^3}+\frac{d^3 \log \left (\frac{2}{1-i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )^2}{e^4}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{e^4}+\frac{2 b d^2 \log \left (\frac{2}{1+i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{c e^3}-\frac{d x^2 \left (a+b \tan ^{-1}(c x)\right )^2}{2 e^2}+\frac{a b d x}{c e^2}+\frac{x^3 \left (a+b \tan ^{-1}(c x)\right )^2}{3 e}-\frac{b x^2 \left (a+b \tan ^{-1}(c x)\right )}{3 c e}-\frac{b^2 d \log \left (c^2 x^2+1\right )}{2 c^2 e^2}+\frac{b^2 x}{3 c^2 e}-\frac{b^2 \tan ^{-1}(c x)}{3 c^3 e}+\frac{b^2 d x \tan ^{-1}(c x)}{c e^2} \]
Antiderivative was successfully verified.
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Rule 4876
Rule 4846
Rule 4920
Rule 4854
Rule 2402
Rule 2315
Rule 4852
Rule 4916
Rule 260
Rule 4884
Rule 321
Rule 203
Rule 4858
Rubi steps
\begin{align*} \int \frac{x^3 \left (a+b \tan ^{-1}(c x)\right )^2}{d+e x} \, dx &=\int \left (\frac{d^2 \left (a+b \tan ^{-1}(c x)\right )^2}{e^3}-\frac{d x \left (a+b \tan ^{-1}(c x)\right )^2}{e^2}+\frac{x^2 \left (a+b \tan ^{-1}(c x)\right )^2}{e}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2}{e^3 (d+e x)}\right ) \, dx\\ &=\frac{d^2 \int \left (a+b \tan ^{-1}(c x)\right )^2 \, dx}{e^3}-\frac{d^3 \int \frac{\left (a+b \tan ^{-1}(c x)\right )^2}{d+e x} \, dx}{e^3}-\frac{d \int x \left (a+b \tan ^{-1}(c x)\right )^2 \, dx}{e^2}+\frac{\int x^2 \left (a+b \tan ^{-1}(c x)\right )^2 \, dx}{e}\\ &=\frac{d^2 x \left (a+b \tan ^{-1}(c x)\right )^2}{e^3}-\frac{d x^2 \left (a+b \tan ^{-1}(c x)\right )^2}{2 e^2}+\frac{x^3 \left (a+b \tan ^{-1}(c x)\right )^2}{3 e}+\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2}{1-i c x}\right )}{e^4}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}-\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-i c x}\right )}{e^4}+\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}+\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2}{1-i c x}\right )}{2 e^4}-\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 e^4}-\frac{\left (2 b c d^2\right ) \int \frac{x \left (a+b \tan ^{-1}(c x)\right )}{1+c^2 x^2} \, dx}{e^3}+\frac{(b c d) \int \frac{x^2 \left (a+b \tan ^{-1}(c x)\right )}{1+c^2 x^2} \, dx}{e^2}-\frac{(2 b c) \int \frac{x^3 \left (a+b \tan ^{-1}(c x)\right )}{1+c^2 x^2} \, dx}{3 e}\\ &=\frac{i d^2 \left (a+b \tan ^{-1}(c x)\right )^2}{c e^3}+\frac{d^2 x \left (a+b \tan ^{-1}(c x)\right )^2}{e^3}-\frac{d x^2 \left (a+b \tan ^{-1}(c x)\right )^2}{2 e^2}+\frac{x^3 \left (a+b \tan ^{-1}(c x)\right )^2}{3 e}+\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2}{1-i c x}\right )}{e^4}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}-\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-i c x}\right )}{e^4}+\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}+\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2}{1-i c x}\right )}{2 e^4}-\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 e^4}+\frac{\left (2 b d^2\right ) \int \frac{a+b \tan ^{-1}(c x)}{i-c x} \, dx}{e^3}+\frac{(b d) \int \left (a+b \tan ^{-1}(c x)\right ) \, dx}{c e^2}-\frac{(b d) \int \frac{a+b \tan ^{-1}(c x)}{1+c^2 x^2} \, dx}{c e^2}-\frac{(2 b) \int x \left (a+b \tan ^{-1}(c x)\right ) \, dx}{3 c e}+\frac{(2 b) \int \frac{x \left (a+b \tan ^{-1}(c x)\right )}{1+c^2 x^2} \, dx}{3 c e}\\ &=\frac{a b d x}{c e^2}-\frac{b x^2 \left (a+b \tan ^{-1}(c x)\right )}{3 c e}+\frac{i d^2 \left (a+b \tan ^{-1}(c x)\right )^2}{c e^3}-\frac{d \left (a+b \tan ^{-1}(c x)\right )^2}{2 c^2 e^2}-\frac{i \left (a+b \tan ^{-1}(c x)\right )^2}{3 c^3 e}+\frac{d^2 x \left (a+b \tan ^{-1}(c x)\right )^2}{e^3}-\frac{d x^2 \left (a+b \tan ^{-1}(c x)\right )^2}{2 e^2}+\frac{x^3 \left (a+b \tan ^{-1}(c x)\right )^2}{3 e}+\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2}{1-i c x}\right )}{e^4}+\frac{2 b d^2 \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1+i c x}\right )}{c e^3}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}-\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-i c x}\right )}{e^4}+\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}+\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2}{1-i c x}\right )}{2 e^4}-\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 e^4}-\frac{\left (2 b^2 d^2\right ) \int \frac{\log \left (\frac{2}{1+i c x}\right )}{1+c^2 x^2} \, dx}{e^3}+\frac{\left (b^2 d\right ) \int \tan ^{-1}(c x) \, dx}{c e^2}+\frac{b^2 \int \frac{x^2}{1+c^2 x^2} \, dx}{3 e}-\frac{(2 b) \int \frac{a+b \tan ^{-1}(c x)}{i-c x} \, dx}{3 c^2 e}\\ &=\frac{a b d x}{c e^2}+\frac{b^2 x}{3 c^2 e}+\frac{b^2 d x \tan ^{-1}(c x)}{c e^2}-\frac{b x^2 \left (a+b \tan ^{-1}(c x)\right )}{3 c e}+\frac{i d^2 \left (a+b \tan ^{-1}(c x)\right )^2}{c e^3}-\frac{d \left (a+b \tan ^{-1}(c x)\right )^2}{2 c^2 e^2}-\frac{i \left (a+b \tan ^{-1}(c x)\right )^2}{3 c^3 e}+\frac{d^2 x \left (a+b \tan ^{-1}(c x)\right )^2}{e^3}-\frac{d x^2 \left (a+b \tan ^{-1}(c x)\right )^2}{2 e^2}+\frac{x^3 \left (a+b \tan ^{-1}(c x)\right )^2}{3 e}+\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2}{1-i c x}\right )}{e^4}+\frac{2 b d^2 \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1+i c x}\right )}{c e^3}-\frac{2 b \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1+i c x}\right )}{3 c^3 e}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}-\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-i c x}\right )}{e^4}+\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}+\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2}{1-i c x}\right )}{2 e^4}-\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 e^4}+\frac{\left (2 i b^2 d^2\right ) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+i c x}\right )}{c e^3}-\frac{\left (b^2 d\right ) \int \frac{x}{1+c^2 x^2} \, dx}{e^2}-\frac{b^2 \int \frac{1}{1+c^2 x^2} \, dx}{3 c^2 e}+\frac{\left (2 b^2\right ) \int \frac{\log \left (\frac{2}{1+i c x}\right )}{1+c^2 x^2} \, dx}{3 c^2 e}\\ &=\frac{a b d x}{c e^2}+\frac{b^2 x}{3 c^2 e}-\frac{b^2 \tan ^{-1}(c x)}{3 c^3 e}+\frac{b^2 d x \tan ^{-1}(c x)}{c e^2}-\frac{b x^2 \left (a+b \tan ^{-1}(c x)\right )}{3 c e}+\frac{i d^2 \left (a+b \tan ^{-1}(c x)\right )^2}{c e^3}-\frac{d \left (a+b \tan ^{-1}(c x)\right )^2}{2 c^2 e^2}-\frac{i \left (a+b \tan ^{-1}(c x)\right )^2}{3 c^3 e}+\frac{d^2 x \left (a+b \tan ^{-1}(c x)\right )^2}{e^3}-\frac{d x^2 \left (a+b \tan ^{-1}(c x)\right )^2}{2 e^2}+\frac{x^3 \left (a+b \tan ^{-1}(c x)\right )^2}{3 e}+\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2}{1-i c x}\right )}{e^4}+\frac{2 b d^2 \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1+i c x}\right )}{c e^3}-\frac{2 b \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1+i c x}\right )}{3 c^3 e}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}-\frac{b^2 d \log \left (1+c^2 x^2\right )}{2 c^2 e^2}-\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-i c x}\right )}{e^4}+\frac{i b^2 d^2 \text{Li}_2\left (1-\frac{2}{1+i c x}\right )}{c e^3}+\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}+\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2}{1-i c x}\right )}{2 e^4}-\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 e^4}-\frac{\left (2 i b^2\right ) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+i c x}\right )}{3 c^3 e}\\ &=\frac{a b d x}{c e^2}+\frac{b^2 x}{3 c^2 e}-\frac{b^2 \tan ^{-1}(c x)}{3 c^3 e}+\frac{b^2 d x \tan ^{-1}(c x)}{c e^2}-\frac{b x^2 \left (a+b \tan ^{-1}(c x)\right )}{3 c e}+\frac{i d^2 \left (a+b \tan ^{-1}(c x)\right )^2}{c e^3}-\frac{d \left (a+b \tan ^{-1}(c x)\right )^2}{2 c^2 e^2}-\frac{i \left (a+b \tan ^{-1}(c x)\right )^2}{3 c^3 e}+\frac{d^2 x \left (a+b \tan ^{-1}(c x)\right )^2}{e^3}-\frac{d x^2 \left (a+b \tan ^{-1}(c x)\right )^2}{2 e^2}+\frac{x^3 \left (a+b \tan ^{-1}(c x)\right )^2}{3 e}+\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2}{1-i c x}\right )}{e^4}+\frac{2 b d^2 \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1+i c x}\right )}{c e^3}-\frac{2 b \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1+i c x}\right )}{3 c^3 e}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )^2 \log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}-\frac{b^2 d \log \left (1+c^2 x^2\right )}{2 c^2 e^2}-\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2}{1-i c x}\right )}{e^4}+\frac{i b^2 d^2 \text{Li}_2\left (1-\frac{2}{1+i c x}\right )}{c e^3}-\frac{i b^2 \text{Li}_2\left (1-\frac{2}{1+i c x}\right )}{3 c^3 e}+\frac{i b d^3 \left (a+b \tan ^{-1}(c x)\right ) \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{e^4}+\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2}{1-i c x}\right )}{2 e^4}-\frac{b^2 d^3 \text{Li}_3\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 e^4}\\ \end{align*}
Mathematica [F] time = 180.002, size = 0, normalized size = 0. \[ \text{\$Aborted} \]
Verification is Not applicable to the result.
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Maple [C] time = 14.474, size = 2136, normalized size = 3.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{6} \, a^{2}{\left (\frac{6 \, d^{3} \log \left (e x + d\right )}{e^{4}} - \frac{2 \, e^{2} x^{3} - 3 \, d e x^{2} + 6 \, d^{2} x}{e^{3}}\right )} + \frac{2 \, e^{3} \int \frac{36 \,{\left (b^{2} c^{2} e^{3} x^{5} + b^{2} e^{3} x^{3}\right )} \arctan \left (c x\right )^{2} + 3 \,{\left (b^{2} c^{2} e^{3} x^{5} + b^{2} e^{3} x^{3}\right )} \log \left (c^{2} x^{2} + 1\right )^{2} + 4 \,{\left (24 \, a b c^{2} e^{3} x^{5} - 2 \, b^{2} c e^{3} x^{4} - 3 \, b^{2} c d^{2} e x^{2} - 6 \, b^{2} c d^{3} x +{\left (b^{2} c d e^{2} + 24 \, a b e^{3}\right )} x^{3}\right )} \arctan \left (c x\right ) + 2 \,{\left (2 \, b^{2} c^{2} e^{3} x^{5} - b^{2} c^{2} d e^{2} x^{4} + 3 \, b^{2} c^{2} d^{2} e x^{3} + 6 \, b^{2} c^{2} d^{3} x^{2}\right )} \log \left (c^{2} x^{2} + 1\right )}{c^{2} e^{4} x^{3} + c^{2} d e^{3} x^{2} + e^{4} x + d e^{3}}\,{d x} + 4 \,{\left (2 \, b^{2} e^{2} x^{3} - 3 \, b^{2} d e x^{2} + 6 \, b^{2} d^{2} x\right )} \arctan \left (c x\right )^{2} -{\left (2 \, b^{2} e^{2} x^{3} - 3 \, b^{2} d e x^{2} + 6 \, b^{2} d^{2} x\right )} \log \left (c^{2} x^{2} + 1\right )^{2}}{96 \, e^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b^{2} x^{3} \arctan \left (c x\right )^{2} + 2 \, a b x^{3} \arctan \left (c x\right ) + a^{2} x^{3}}{e x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \arctan \left (c x\right ) + a\right )}^{2} x^{3}}{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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